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BY 4.0 license Open Access Published by De Gruyter January 6, 2022

Singular quasilinear convective elliptic systems in ℝN

  • Umberto Guarnotta , Salvatore Angelo Marano EMAIL logo and Abdelkrim Moussaoui

Abstract

The existence of a positive entire weak solution to a singular quasi-linear elliptic system with convection terms is established, chiefly through perturbation techniques, fixed point arguments, and a priori estimates. Some regularity results are then employed to show that the obtained solution is actually strong.

MSC 2010: 35J47; 35J75; 35B08; 35D35

1 Introduction and main result

In this paper, we deal with the problem

(P) Δpu=f(x,u,v,u,v)inRN,Δqv=g(x,u,v,u,v)inRN,u,v>0inRN,

where N3,21N<p,q<N,Δrz:=div(|z|r2z) denotes the r-Laplacian of z for 1 < r < +∞, while f,g:RN×(0,+)2×R2N(0,+) are Carathéodory functions satisfying assumptions H1–H3 below.

Problem (P) exhibits three interesting features:

  • The reaction terms f and g can be singular at zero.

  • f , g depend on the gradient of solutions.

  • Equations are set in the whole space RN.

  • However, they give rise to some nontrivial difficulties, such as the loss of variational structure and the lack of compactness for Sobolev embedding. This work continues the study started in [32], whose setting was RN and convective terms did not appear, along the very recent papers [6, 23, 24, 31], which address analogous questions, but concerning a bounded domain.

Primarily, we need an appropriate functional framework where to treat the problem, mainly because the integrability properties of solutions and their gradients may differ at infinity, as the example in [20, p. 80] shows. Accordingly, one is led to employ the so-called Beppo Levi (or homogeneous Sobolev) spaces D01,r(RN), systematically studied for the first time by Deny and Lions [15]. The monographs [20, 29, 38] provide an exhaustive introduction on the topic.

Let X:=D01,p(RN)×D01,q(RN) and let r' denote the conjugate exponent of r > 1. A pair (u, v) ∈ X such that u, v > 0 a.e. in RN is called:

  1. distributional solution to (P) if for every (φ1,φ2)C0(RN)2 one has

(1.1) RN|u|p2uφ1dx=RNf(,u,v,u,v)φ1dx,RN|v|q2vφ2dx=RNg(,u,v,u,v)φ2dx;
  1. (weak) solution of (P) when (1.1) holds for all (φ1, φ2) ∈ X;

  2. ‘strong’ solution to (P) if |u|p2u,|v|q2vWloc1,2(RN) and the differential equations are satisfied a.e. in RN.

Obviously, both 2) and 3) force 1), whilst reverse implications turn out generally false; see also Remark 4.5. Moreover, as observed at p. 48 of [38], problems in unbounded domains may admit strong solutions that are not weak or vice-versa. So, the search for strong solutions appears of some interest in this context.

Roughly speaking, our technical approach proceeds as follows. We first solve an auxiliary problem (Pε), ε > 0, obtained by shifting variables of reactions, which avoids singularities. To do this, nonlinear regularity theory, a priori estimates,Moser’s iteration, trapping region, and fixed point arguments are employed. Unfortunately, bounds from above alone do not allow to get a solution of (P): treating singular terms additionally requires some estimates from below. Theorem 3.1 in [14] ensures that solutions to (Pε) turn out locally greater than a positive constant regardless of ε. Thus, under hypotheses H1–H3 below, we can construct a sequence {(uε , vε)} ⊆ X such that (uε , vε) solves (Pε) for all ε > 0 and whose weak limit as ε → 0+ is a distributional solution to (P); cf. Lemma 4.1. Next, a localization-regularization reasoning (see Lemma 4.2) shows that

(u, v) distributional solution (u, v) weak solution.

Through a recent differentiability result [10, Theorem 2.1] one then has

(u, v) distributional solution (u, v) strong solution;

cf. Lemma 4.3. Further, (u,v)Cloc1,α(RN) once condition H3 is slightly strengthened; see Remark 4.4.

Singular elliptic problems, either in bounded domains or in RN, have a long history, that traces back to [12, 28] and [8, 9, 13, 25, 27] for semi-linear equations. More recent results, involving also systems, can be found in [17, 32, 33, 36] and the references therein. A very fruitful approach has been developed in [3, 4]; see also [7] and [34]. Existence, regularity, and qualitative properties of the solutions have been investigated, e.g., in [1, 2, 11, 19, 30, 40].

Henceforth, the assumptions below will be posited. If 1 < r < N then, by definition, r:=NrNr.

H1(f)There exist α1(1,0],β1,δ1[0,q1),γ1[0,p1),m1,mˆ1>0, and a1Llocsp(RN), with sp>pN,

such that

m1a1(x)s1α1s2β1f(x,s1,s2,t1,t2)mˆ1a1(x)s1α1s2β1+|t1|γ1+|t2|δ1

in RN × (0,+∞)2 × R2N. Moreover, essBρinfa1>0 for all ρ > 0.

H1(g)There exist β2(1,0],α2,γ2[0,p1),δ2[0,q1),m2,mˆ2>0, and a2Llocsq(RN), with sq>qN,

such that

m2a2(x)s1α2s2β2g(x,s1,s2,t1,t2)mˆ2a2(x)s1α2s2β2+|t1|γ2+|t2|δ2

in RN × (0,+∞)2 × R2N. Moreover, ess infBρa2>0 for all ρ > 0.

H1(a)There exist ζ1, ζ2 (N, +∞] such that aiL1(RN)Lζi(RN),i=1,2, where

1ζ1<1ppθ1,1ζ2<1qqθ2,

with

θ1:=maxβ1q,γ1p,δ1q<1pp,θ2:=maxα2p,γ2p,δ2q<1qq.

H2 If η1 := max1, δ1} and η2 := max2, γ2} then

η1η2<(p1γ1)(q1δ2).

H3 One has

1sp+maxγ1p,δ1q12,1sq+maxγ2p,δ2q12.

Example 1.1

H1(a) is fulfilled once a1,a2L1(RN)L(RN) and

maxβ1q,γ1p,δ1q<1pp,maxα2p,γ2p,δ2q<1qq.

In fact, it suffices to choose ζ1 := ζ2 := +∞.

Remark 1.2

By interpolation (see, e.g., [32, Proposition 2.1]), condition H1(a) entails aiLσi,j(RN),i=1,2, where:

(i) σ1,j:=11tj,j=1,2,3,4, with

t1=α1+1p+β1q,t2=1p+β1q,t3=1p+γ1p,t4=1p+δ1q;

(ii) σ2,j:=11tj,j=1,2,3,4, with

t1=β2+1q+α2p,t2=1q+α2p,t3=1q+γ2p,t4=1q+δ2q.

The aim of this paper is to prove the following

Theorem 1.3

Under hypotheses H1H3, problem (P) admits a weak and strong solution (u, v) ∈ X.

2 Preliminaries

Let Z be a Hausdorff topological space and let T : Z → Z be continuous. Following [22, p. 2], the operator T is called compact when T(Z) turns out a compact subset of Z. If Z is a normed space, {zn}⊆ Z, and z ∈ Z then zn → z in Z means that the sequence {zn} strongly converges to z,while zn z stands for weak convergence. As usual, Z* denotes the topological dual of Z and Z2 := Z × Z.

Hereafter, N ≥ 3 is a fixed integer, B(x, ρ) indicates the open ball in RN of radius ρ > 0 centered at x ∈ RN and Bρ := B(0, ρ), while |E| stands for the Lebesgue measure of E.

Let Z := Z(Ω) be a real-valued function space on a nonempty measurable set Ω ⊆ RN. If z1, z2 ∈ Z and z1(x) < z2(x) a.e. in Ω then we simply write z1 < z2. The meaning of z1z2, etc. is analogous. Put

Z+:={zZ:z>0}.

Given {zn}⊆ Z and z ∈ Z, the symbol zn ↑ z signifies that {zn} is monotone increasing and zn(x) → z(x) for almost every x ∈ Ω. Moreover,

z±:=max{±z,0},suppz:={xΩ:z(x)0}.

When Ω := RN, we write z ∈ Zloc(RN) if for every nonempty compact subset K of RN the restriction zK belongs to Z(K). Similarly, a sequence {zn}Zloc(RN) is called bounded in Zloc(RN) once the same holds for {znK} in Z(K), with any K as above.

Let 1 < r < N and let z : RN R be a measurable function. Throughout the paper, r:=rr1,r:=NrNr,

zr:=RN|z(x)|rdx1/r,z:=esssupxRN|z(x)|.

We now recall the notion and some relevant properties of Beppo Levi’s spaceD01,r(RN), addressing the reader to [20, Chapter II] for a complete treatment. Put

D1,r:=zLloc1(RN):|z|Lr(RN)

and denote by R the equivalence relation that identifies two elements in D1,r whose difference is a constant. The quotient set D˙1,r, endowed with the norm

z1,r:=RN|z(x)|rdx1/r,

turns out complete. Write D01,r(RN) for the subspace of D˙1,r defined as the closure of C0(RN) under · 1,r, namely

D01,r(RN):=C0(RN)1,r.

D01,r(RN), usually called Beppo Levi space, is reflexive and continuously embeds in Lr(RN), i.e.,

(2.1) D01,r(RN)Lr(RN).

Consequently, if zD01,r(RN) then z vanishes at infinity, meaning that the set {x ∈ RN : |z(x)|ε} has finite measure for any ε > 0. In fact, by Chebichev’s inequality and (2.1), one has

|{xRN:|z(x)|ε}|εrzrr(cε1z1,r)r<+,

where c > 0 is the best constant related to (2.1); see the seminal paper [39].

Hereafter, c, cε, and cε(·) will denote generic positive constants, which may change explicit value from line to line. Subscripts and/or arguments emphasize their dependence on a given variable.

To avoid cumbersome expressions, define

X:=D01,p(RN)×D01,q(RN),(u,v):=u1,p+v1,q(u,v)X,C+1:=X+Cloc1(RN)2,C+1,α:=X+Cloc1,α(RN)2.

C+1 and C+1,α will be endowed with the topology induced by that of X.

The following a priori estimate will play a basic role in the sequel.

Lemma 2.1

Let 21N<r<+, let ζ > N, and let hL1(RN)Lζ(RN).IfzD01,r(RN)Cloc1(RN) is a weak solution toΔrz = h(x) in RN then there exists c > 0, independent of z, such that

zr1cinfR>0R1Nζhζ+RNrzrr1.

Proof. Pick any x ∈ RN and R > 0. Via [26, Theorem 1.1], when r ≥ 2, or [18, Theorem 1.1], if 21N<r<2, with Ω := B(x, R) and μ := hdx, as well as Hölder’s inequality, we easily get

|z(x)|r1c0RρNB(x,ρ)|h|dydρ+RNB(x,R)|z|dyr1chζ0RρNζdρ+Rr1rNzrr1cR1Nζhζ+RNrzrr1,

where c > 0 does not depend on z, h, x, and R; see [18, Remark 1.3]. Taking the infimum in R > 0 on the right and the supremum in x ∈ RN on the left yields the conclusion.

3 The regularized system

3.1 ‘Freezing’ the right-hand side

Fix w:=w1,w2C+1,ε>0 and define

fw,ε:=f,w1+ε,w2,w,gw,ε:=g,w1,w2+ε,w,

where ∇w := (∇w1,∇w2). We first focus on the auxiliary problem

(PEW) Δpu=fw,ε(χ) in RN.Δqv=gw,ε(χ) in RN,

Lemma 3.1

If H1 holds then PWε admits a unique solution (u,v)C+1,α, for a suitable α ∈ (0, 1).

Proof. Hypothesis H1 and (2.1) guarantee that (fw,ε , gw,ε) ∈ X*. Hence, by Minty-Browder’s Theorem [5, Theorem 5.16], problem PWε possesses a unique solution (u, v) ∈ X. Thanks to H1 again one has

fw,ε,gw,εLloc spRN×Lloc sqRN.

Thus, standard results from nonlinear regularity theory [16, p. 830] entail (u,v)Cloc 1,αRN2. Testing the first equation in PWε with u we next obtain

upp=RNfw,εudx0,

because f is non-negative, which forces u ≥ 0. Likewise, v ≥ 0. The strong maximum principle [35, Theorem 1.1.1] finally yields (u, v) ∈ X+.

Throughout this sub-section, (u, v) will denote the solution to PWε given by Lemma 3.1.

Lemma 3.2

Let H1 be satisfied. Then there exists Lε > 0 such that

upp1Lε1+w1pγ1+w2qη1,vqq1Lε1+w1pη2+w2qδ2,

where η1 := max1, δ1} and η2 := max2, γ2}.

Proof. Test the first equation in PWε with u and exploit H1(f), H1(a), besides (2.1), to achieve

(3.1) upp=RNf,w1+ε,w2,w1,w2udxmˆ1RNa1w1+εα1w2β1+w1γ1+w2δ1udxmˆ1RNa1max1,εα1w2β1+w1γ1+w2δ1udxcEupw2qβ1+w1pγ1+w2qδ1cεupw2qβ1+w1pγ1+w2qδ1Lεup1+w1pγ1+w2qη1,

because

(3.2) w2qβ1+w2qδ121+w2qη1.

This shows the first inequality. The other is verified similarly.

Lemma 3.3

Under H1, there exists Mε:=Mεw1p,w2q>0 such that

maxu,vMεw1p,w2q.

Proof. The proof can be made by adapting the one of Lemma 3.3 in [32]. So, we will briefly focus the key-points only. Fix any ξ11,pp such that

(3.3) 1ζ1<11ξ1θ1,

where ζ1 and θ1 come from H1(a). Set uK := min{u, K}, K > 1, and test Pwε with φ:=uKkp+1,k0. Fatou’s Lemma, Hölder’s inequality joined to H1(a), Sobolev’s embedding (2.1), and (3.2) produce

kp+1(k+1)pu(k+1)p(k+1)pkp+1(k+1)plim infK+uK(k+1)p(k+1)pcmax1,εα1RNa1w2β1+w1γ1+w2δ1ukp+1dxcεw2qβ1+w1pγ1+w2qδ1u(kp+1)ξ1kp+1cε1+w1pγ1+w2qη1u(kp+1)ξ1kp+1;

cf. [32, pp. 1587–1588], but replacing ξ1withξ1. Moreover,

(k+1)p>(kp+1)ξ1k0

as ξ1<pp. Hence, Moser’s iteration can start, and we obtain u∞ ≤ Mε, where

Mε:=cε1+w1pγ1+w2qη1τ

for some τ > 0; details can be read in [32, pp. 1588–1590], replacing ξ1withξ1 as above. A similar argument applies to v.

Lemma 3.4

If H1 holds and maxwi,wi<+,i=1,2, then

up1Nεw1p,w2q,w21+w1γ1+w2δ1,vq1Nεw1p,w2q,w11+w1γ2+w2δ2

with suitable constants Nεw1p,w2q,wi>0,i=1,2.

Proof. Lemma 3.1 ensures that uD01,pRNCloc1RN, while H1 entails fw,εL1RNLζ1RN. By Lemma 2.1, besides H1 again, we thus have

up1cfw,εζ1+upp1cmax1,εα1a1ζ1w2β1+w1γ1+w2δ1+upp1cεw2β1+w1γ1+w2δ1+upp1.

Now, using Lemma 3.2 yields

up1cεw2β1+w1γ1+w2δ1+w1pγ1+w2qη1+1Nεw1p,w2q,w21+w1γ1+w2δ1,

where

Nεw1p,w2q,w2:=cε1+w2β1+w1pγ1+w2qη1.

This shows the first inequality. The other is analogous.

3.2 Regularizing the right-hand side

Let H1 be satisfied. Given ε > 0, define

Rε:=w1,w2C+1:w1pA1,w2qA2wiBi,wiCi,i=1,2,

with Ai , Bi , Ci > 0, i = 1, 2, such that

(3.4) A1p1Lε1+A1γ1+A2η1,A2q1Lε1+A1η2+A2δ2,B1,B2MεA1,A2,C1p1NεA1,A2,B21+C1γ1+C2δ1,C2q1NεA1,A2,B11+C1γ2+C2δ2,

and Lε, Mε(,),Nε(,,) stemming from Lemmas 3.23.4. Apropos, system (3.4) admits solutions. In fact, by H1, we can pick

(3.5) 1<σ<(p1)(q1)η1η2.

If A1:=K1η2andA2:=Kσq1 then the first two inequalities of (3.4) become

Kp1η2Lε1+Kγ1η2+Kση1q1,KσLε1+K+Kσδ2q1,

which, due to (3.5), are true for any sufficiently large K > 0. Next, choose

B1:=B2:=MεK1η2,Kσq1.

With Ai, Bi as above, set C1:=H1η2andC2:=Hσq1 The last two inequalities in (3.4) rewrite as

Hp1η2NεA1,A2,B21+Hγ1η2+Hσδ1q1,HσNεA1,A2,B11+Hγ2η2+Hσδ2q1.

Thanks to (3.5) again, they hold for every H > 0 big enough.

On the trapping region Rε we will consider the topology induced by that of X. Let us now investigate the regularized problem

Δpu=f(x,u+ε,v,u,v) in RN,Δqv=g(x,u,v+ε,u,v) in RN,u,v>0 in RN,

where ε ≥ 0. Evidently, (Pε) reduces to (P) once ε = 0.

Lemma 3.5

Under H1, for every ε > 0 problem (Pε) possesses a solution uε,vεC+1,α.

Proof. Fix ε > 0 and define, provided w ∈ Rε,

Tε(w):=(u,v),with(u,v)being the unique solution toPwε;

cf. Lemma 3.1. From Lemmas 3.23.4, besides (3.4), it follows TεRεRε. Claim 1. TεRε is relatively compact in X.

To see this, pick wnRε, put

wn:=w1,n,w2,n,un,vn:=Tεwn,nN,

and understand any convergence up to sub-sequences. Since TεwnRε while X is reflexive, un,vn weakly converges to a point (u, v) ∈ X. Taking any ρ > 0, if Yρ := Lp(BρLq(Bρ), then one has

(3.6) XW1,pBρ×W1,qBρYρ.

Actually, the first embedding in (3.6) is continuous by (2.1) and the continuity of the restriction map Lr(RN) → Lr(Bρ), while the other one is compact due to Rellich-Kondrakov’s theorem [5, Theorem 9.16]. Thus, XYρ compactly, which yields (un , vn) (u, v) in Yρ. Let us next verify that

(3.7) un(x),vn(x)(u(x),v(x)) for almost every xRN.

In fact, (un , vn) (u, v) in Y1 yields a sub-sequence un(1),vn(1)ofun,vn such that

un(1)(x),vn(1)(x)(u(x),v(x)) for almost all xB1.

Since un(1),vn(1)(u,v)inY2 we can extract a sub-sequence un(2),vn(2)fromun(1),vn(1) fulfilling

un(2)(x),vn(2)(x)(u(x),v(x)) for almost every xB2. .

By induction, to each k ≥ 2 there corresponds a sub-sequence un(k),vn(k)ofun(k1),vn(k1) such that

un(k)(x),vn(k)(x)(u(x),v(x)) for almost all xBk.

Now, Cantor’s diagonal procedure leads to un(n),vn(n)(u,v) a.e. in RN, because k=1Bk=RN, and (3.7) follows.

Through H1(f), besides the inclusion wnRε, we get

(3.8) RNunp2ununudx=RNf,w1,n+ε,w2,n,wnunudxRNf,w1,n+ε,w2,n,wnunudxcεRNa1unudxnN,

with cε:=mˆ1εα1B2β1+C1γ1+C2δ1. Using TεRεRε and (3.7) one has

a1unu2B1a1L1RN,nN.

So, by (3.7)–(3.8), Lebesgue’s Theorem entails

lim supnRNunp2ununudxcεlimnRNa1unudx=0.

Now, recall (cf., e.g., [32, Proposition 2.2]) that the operator Δp,D01,pRN is of type (S)+ to achieve un → u in D01,pRN. A similar reasoning applies to {vn}.

Claim 2. Tε:RεRε is continuous.

Let wnRε and wRε satisfy wn → w in X. Thanks to (2.1), Theorem 4.9 of [5] provides

(3.9) wn(x)w(x) and wn(x)w(x) for almost every xRN.

Morever, if (un , vn) := Tε(wn), n ∈ N, then there exists a point (u, v) ∈ X such that (un , vn) (u, v) in X; see the proof of Claim 1. Arguing as before, we obtain

(3.10) un(x)u(x) and un(x)u(x) for almost every xRN.

Since unpA1 whatever n, the sequence unp2unLpRN turns out bounded. Due to (3.10) and [5, Exercise 4.16], this yields

(3.11) limnRNunp2unφdx=RN|u|p2uφdx,φD01,pRN.

On the other hand,

(3.12) limnRNf(,w1,n+ε,w2,n,wn)φdx=RNf(,w1+ε,w2,w)φdx

by Lebesgue’s Theorem jointly with (3.9) and the inequality

f(,w1,n+ε,w2,n,wn)|φ|cεa1|φ|L1(RN)nN,

which easily arises from H1(f) besides the choice of Rε. Finally,

(3.13) RN|un|p2unφdx=RNf(,w1,n+ε,w2,n,wn)φdx,nN,

because (un , vn) solves (Pwnε). Gathering (3.11)–(3.13) together we have

RN|u|p2uφdx=RNf(,w1+ε,w2,w)φdxφD01,p(RN).

The same is evidently true for v. So, (u, v) turns out a solution to (Pwε). Uniqueness forces (u, v) = Tε(w), whence Tε(wn) → Tε(w).

Now, Theorem 3.2 in [22, p. 119] can be applied, and Tε admits a fixed point (uε,vε)Rε. By definition of Tε, the pair (uε , vε) solves problem (Pε), while Lemma 3.1 gives (uε,vε)C+1,α.

Lemma 3.6

If H1H2 hold then there exists a constant L > 0, independent of ε ≥ 0, such that (u, v)≤ L for every solution (u, v) ∈ X+ to (Pε).

Proof. Pick ε ≥ 0 and suppose (u, v) ∈ X+ solves (Pε). Via H1 and (2.1) one has

(3.14) upp=RNf(,u+ε,v,u,v)udxmˆ1RNa1[(u+ε)α1vβ1+|u|γ1+|v|δ1]udxmˆ1RNa1(uα1+1vβ1+|u|γ1u+|v|δ1u)dxcupα1+1vqβ1+upγ1up+vqδ1upcupα1+1vqβ1+upγ1+1+vqδ1upcmax{1,upγ1+1}max{1,vqη1}.

Likewise,

(3.15) vqqcmax{1,vqδ2+1}max{1,upη2}.

It should be noted that the constant c does not depend on (u, v) and ε. If either vq1 orup1 then (3.14)–(3.15) directly lead to the conclusion, because γ1 +1 < p and δ2 +1 < q; see H1. Hence, we may assume min{up,vq}>1. Dividing (3.14)–(3.15) by upγ1+1 andvqδ2+1, respectively, yields

uppγ11cvqη1,vqqδ21cupη2.

This clearly entails

uppγ11cupη1η2qδ21,vqqδ21cvqη1η2pγ11.

The conclusion now follows from H2.

Lemma 3.7

Let H1H2 be satisfied. Then there exists M > 0, independent of ε ≥ 0, such that

maxu,vM

for every solution (u,v)X+to Pε.

Proof. The proof is similar to that one of Lemma 3.3. With the same notation, fix ε ≥ 0, suppose (u, v) ∈ X+ solves (Pε), and define Ω1 := {x ∈ RN : u(x) ≥ 1}. Moreover, given z ∈ Lr(RN), r > 1, write zr in place of zLrΩ1 when no confusion can arise. Exploiting H1(f) one has

Ω1|u|p2uφdxmˆ1Ω1a1vβ1+|u|γ1+|v|δ1φdx

for all φD01,pRN+; cf. [32, Lemma 3.2]. If φ:=uKkp+1,k0, then Fatou’s Lemma, Hölder’s inequality combined with H1(a), Sobolev’s embedding (2.1), and Lemma 3.6 produce

kp+1(k+1)pu(k+1)p(k+1)pkp+1(k+1)plim infK+uK(k+1)p(k+1)pcΩ1a1vβ1+|u|γ1+|v|δ1ukp+1dxcvqβ1+upγ1+vqδ1u(kp+1)ξ1kp+1cu(kp+1)ξ1kp+1,

where ξ11,pp fulfills (3.3) while c does not depend on (u, v) and ε. We now proceed exactly as in the proof of Lemma 3.3, getting uM. The other inequality is analogous.

Lemma 3.8

Assume H1H2. Then to every ρ > 0 there corresponds σρ > 0 such that

(3.16) minessinfBρu,essinfBρvσρ

for all (u, v) ∈ X+ distributional solution of (Pε), with 0 ≤ ε ≤ 1.

Proof. Fix ρ > 0. Conditions H1(f)–H1(g), besides Lemma 3.7, entail

f(,u+ε,v,u,v)m1essinfBρa1(M+1)α1vβ1,g(,u,v+ε,u,v)m2essinfBρa2(M+1)β2uα2

a.e. in Bρ. From [14, Theorem 3.1] it thus follows

essinfBρup1cρBρBρvβ1dxcρ(essinfv)β1,essinfBρvq1cρBρBρuα2dxcρessinfBρuα2,

which easily give

essinfBρuCρessinfBρu(p1)(q1)α2β1,assinfBρvCρessinfBρv(p1)(q1)α2β1.

Now, (3.16) is a simple consequence of H1, because α2β1 < (p − 1)(q − 1).

4 Proof of the main result

Lemma 4.1

Under H1H3, problem (P) possesses a distributional solution (u, v) ∈ X+.

Proof. Let εn:=1n,nN. Lemma 3.5 furnishes a sequence un,vnC+1 such that (un , vn) solves Pεn for all n ∈ N. Since X is reflexive, by Lemma 3.6 one has (un , vn) (u, v) in X, where a sub-sequence is considered when necessary. As before (cf. the proof of Lemma 3.5), this forces (3.7). Moreover, (u, v) ∈ X+ because, thanks to Lemma 3.8, to each ρ > 0 there corresponds σρ > 0 satisfying

(4.1) mininfBρun,infBρvnσρnN.

Claim. For every ρ > 0, and along a sub-sequence if necessary, one has

(4.2) un,vn(u,v) in W1,pBρ×W1,qBρ.

Likewise the proof of (3.9), this will force

(4.3) un,vn(u,v) a.e. in RN.

Let ρ > 0. Hypothesis H1, (4.1), Lemma 3.7, and H3 yield

(4.4) f,un+1/n,vn,un,vnmˆ1a1un+1/nα1vnβ1+unγ1+vnδ1 in B2ρmˆ1σ2ρα1Mβ1+unγ1+vnδ1a1L2B2ρ

whatever n. So, [10, Theorem 2.1] combined with Lemma 3.6 ensures that unp2un turns out bounded in W1,2(Bρ). Since p>21N, by Rellich-Kondrakov’s theorem [5, Theorem 9.16], the embedding W1,2Bρ LpBρ is compact. Thus, up to sub-sequences,

(4.5) unp2unU in LpBρ.

Next, observe that the linear operator

zD01,pRNz BρLpBρ

turns out well-defined and continuous in the strong topologies. Therefore,

(4.6) unu in LpBρ;

cf. [5, Theorem 3.10]. Gathering [5, Proposition 3.5] and (4.5)–(4.6) together gives

limnBρunp2ununudx=0.

Since Δp,W1,pBρ enjoys the (S)+-property, we easily achieve unu in W1,pBρ. A similar conclusion holds for {vn}, which shows (4.2).

Now, to verify that (u, v) is a distributional solution of (P), pick any φ1,φ2C0RN2 and choose ρ > 0 fulfilling

suppφ1suppφ2Bρ.

By (4.2), [5, Theorem 4.9] furnishes (h,k)LpBρ×LqBρ such that

unh,vnka.e. inBρand for allnN,

whence

f,un+1/n,vn,un,vnφ1cρ1+hγ1+kδ1a1φ1L1RN,nN,

through (4.4). So, thanks to (3.7) and (4.3), Lebesgue’s Theorem entails

limnRNf,un+1/n,vn,un,vnφ1dx=RNf(,u,v,u,v)φ1dx.

On account of (4.5) and (4.3), we then get

limnRNunp2unφ1dx=RN|u|p2uφ1dx.

Recalling that each (un , vn) weakly solves Pεn produces

RN|u|p2uφ1dx=RNf(,u,v,u,v)φ1dx.

Likewise,

RN|v|p2vφ2dx=RNg(,u,v,u,v)φ2dx,

and the assertion follows.

Lemma 4.2

Let H1H2 be satisfied and let (u, v) ∈ X+ be a distributional solution to problem (P). Then (u, v) weakly solves (P).

Proof. We evidently have, for any φD01,pRN,

(4.7) φ=φ+φ.

Due to the nature of φ+, a localization-regularization procedure will be necessary. With this aim, fix θ ∈ C([0,+)) such that

(4.8) θ(t)=1 if 0t1,0 when t2,θ is decreasing in (1,2)

and a sequence ρkC0RN of standard mollifiers [5, p. 108]. Define, for every n, k ∈ N,

θn():=θ(||/n)C0RN,φn:=θnφ+D01,pRN,ψkn:=ρkφnC0RN.

Using (4.8) we easily get φnφ+. Moreover, limkψk,n=φninD01,pRN which entails

(4.9) limkRN|u|p2uψk,ndx=RN|u|p2uφndx,nN.

If, to shorten notation,fˆ:=f(,u,v,u,v) then the linear functional

ψD01,pRNB2n+2fˆψdx

turns out continuous. In fact, Lemmas 3.7 – 3.8, Hölder’s inequality combined with H1(a), and (2.1) produce

B2n+2a1uα1vβ1|ψ|dxσ2n+2α1Mβ1a1pψpcnψp.

Now, the assertion follows from H1(f), because convection terms can be estimated as already made in (3.14). Observe next that

suppψk,nsuppρk+suppφnB1+B2nB2n+2n,kN;

see [5, Proposition 4.18]. Hence,

(4.10) suppψk,nsuppρk+suppφnB1+B2nB2n+2n,kN.

On the other hand, the hypothesis (u, v) ∈ X+ distributional solution to (P) evidently forces

RN|u|p2uψk,ndx=RNfˆψk,ndx,k,nN.

Letting k → +∞ and exploiting (4.9)–(4.10) we thus achieve

(4.11) RN|u|p2uφndx=RNfˆφndxnN.

Claim. φnφ+in D01,pRN.

In fact, for every n ∈ N one has

(4.12) RNφnφ+pdx=RNφ+θn+θnφ+φ+pdxCRN1θnpφ+pdx+B2nBnθnpφ+pdxCRN1θnpφ+pdx+CB2nBnθnppppdx1ppB2nBnφ+pdxpp=CRN1θnpφ+pdx+cθnNpB2nBnφ+pdxpp.

Recall that φ+D01,pRN. By (4.8), Lebesgue’s Theorem yields

(4.13) limnRN1θnpφ+pdx=0

while, on account of (2.1),

(4.14) limnB2nBnφ+pdx=0.

Since, due to (4.8) again,

RNθnNdx=1nNRNθ|x|nNdx=RNθ(|x|)Ndx<+nN,

gathering (4.12)–(4.14) together shows the claim.

Consequently,

(4.15) limnRN|u|p2uφndx=RN|u|p2uφ+dx.

From φnφ+and fˆ0 it then follows

(4.16) limnRNfˆφndx=RNfˆφ+dx

by Beppo Levi’s Theorem. Through (4.11), (4.15)–(4.16) we thus arrive at

RN|u|p2uφ+dx=RNfˆφ+dx.

Likewise, one has

RN|u|p2uφdx=RNfˆφdx,

whence (cf. (4.7))

RN|u|p2uφdx=RNf(,u,v,u,v)φdxφD01,pRN.

An analogous argument applies to the second equation in (P).

Lemma 4.3

Let H1H3 be satisfied and let (u, v) ∈ X+ be a distributional solution of (P). Then (u, v) strongly solves (P).

Proof. Reasoning as before (see (4.4)) provides f(,u,v,u,v)Lloc2RN. Thanks to [10, Theorem 2.1], this implies |u|p2uWloc 1,2RN. Moreover,

Δpu(x)=f(x,u(x),v(x),u(x),v(x)) a.e. in RN

because of [5, Corollary 4.24]. Similarly about v and the other equation.

Proof of Theorem 1.3.

Lemmas 4.14.3 directly give the conclusion.

Remark 4.4

If H3 is replaced by the stronger condition

H3_ One has

1sp+maxγ1p,δ1q<1pN,1sq+maxγ2p,δ2q<1qN

then any distributional solution (u, v) ∈ X+ to (P) actually lies in C+1,α, with α ∈ (0, 1). To show this, pick Sˆp,Sˆq>0 such that

1sp+maxγ1p,δ1q1sˆp<1pN,1sq+maxγ2p,δ2q1sˆq<1qN.

As in the proof of (4.4), for every ρ > 0 one has

f(,u,v,u,v)cρa11+|u|γ1+|v|δ1LsˆpBρ,g(,u,v,u,v)cρa21+|u|γ2+|v|δ2LsˆqBρ.

Hence, known nonlinear regularity results [16, p. 830] entail (u,v)C+1,α.

Remark 4.5

Unfortunately, we were not able to find in the literature a definition of strong solution for elliptic equations driven by non-linear operators in divergence form. The one adopted here represents a quite natural extension of the semi-linear case p = 2, where it is asked that the solution uWloc2,2(RN) and satisfies the differential equation a.e. in RN; cf. [21, p. 219] and [38, pp. 7–8]. We cannot expect uWloc2,q(RN) for some q > 1, as the example of [10, Remark 2.7] shows. Nevertheless, if (u,v)C+1 is a distributional solution to (P) then u,vWloc2,2(RN) once 1 < p, q < 3; see [37, p. 2]. On the other hand, each strong solution turns out distributional. So, our notion of strong solution should be read as a distributional solution with an extra differentiability property on the fields |u|p2u and |v|q2v.

Acknowledgments

The authors thank S.J.N. Mosconi for helpful and stimulating discussions.

U.Guarnotta and S.A. Marano were supported by the following research projects: 1) PRIN 2017 ‘Nonlinear Differential Problems via Variational, Topological and Set-valued Methods’ (Grant No. 2017AYM8XW) of MIUR; 2) PRA 2020–2022 Linea 2 ‘MO.S.A.I.C.’ of the University of Catania.

A. Moussaoui was supported by the Directorate-General of Scientific Research and Technological Development (DGRSDT).

  1. Conflict of interest

    Conflict of interest statement: Authors state no conflict of interest.

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Received: 2021-03-10
Accepted: 2021-09-17
Published Online: 2022-01-06

© 2021 Umberto Guarnotta et al., published by De Gruyter

This work is licensed under the Creative Commons Attribution 4.0 International License.

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